David Stern calls Nets ‘New York Nets’ during All-Star Game announcement (vid)
It was announced on Wednesday that the two New York-based basketball franchises, the New York Knicks and Brooklyn Nets, will co-host the 2015 edition of the NBA’s All-Star Weekend festivities when the event is held in New York City.
During a press conference on Wednesday, both Commissioner David Stern and NYC Mayor Michael Bloomberg made epic gaffes, Stern’s related to the name of one of the New York NBA franchises and Bloomberg about the two teams meeting in the NBA Finals.
Derps all around.
Said Stern, via the New York Post: “I am pleased to announce that the 2015 NBA All-Star Weekend will be held in New York City, co-hosted by the New York Knicks at Madison Square Garden and the New York Nets at Barclays Center.”
Stern made amends for his abject derpness about the name of one of his league’s franchises, saying, “I called the Nets the New York Nets, and I know they play in Brooklyn, USA. I think it’s New York City, and I think the world is coming to understand that Brooklyn is a very distinct and enjoyable part of New York City.”
Distinct and enjoyable, indeed. But what does Stern care? He’s retiring soon anyway. It’s not like he gives a rip anymore. Just coasting along, like a soon-to-be high school graduate succumbing to the temptations of the “Senior Slide,” that guy.
But the gaffes didn’t end with Stern. Bloomberg had much to say about the budding rivalry between the Nets and Knicks.
“If we were to have a World Series between the Yankees and the Mets, or a Super Bowl between the Jets and the Giants or an NBA championship between these two great teams,” said Bloomberg. “It would be the best thing that ever happened to those leagues.”
If only the New York Knicks and the New York Nets — oops, I mean Brooklyn Nets — could actually meet in the NBA Finals. But there’s one pesky problem with Bloomberg’s idea. Since the teams both reside in the Eastern Conference, there’s absolutely no chance the two teams would ever meet in the NBA Finals.